MANGANESE

This page looks at some aspects of manganese chemistry required for UK A' level exams. It includes: two simple reactions of manganese(II) ions in solution (summarised from elsewhere on the site), and the use of potassium manganate(VII) (potassium permanganate) as an oxidising agent - including its use in titrations.

Reactions of manganese(II) ions in solution

The simplest ion that manganese forms in solution is the hexaaquamanganese(II) ion - [Mn(H₂O)₆]²⁺.

The reaction of hexaaquamanganese(II) ions with hydroxide ions

Hydroxide ions (from, say, sodium hydroxide solution) remove hydrogen ions from the water ligands attached to the manganese ion.

Once a hydrogen ion has been removed from two of the water molecules, you are left with a complex with no charge - a neutral complex. This is insoluble in water and a precipitate is formed.

In the test-tube, the colour changes are:

I have shown the original solution as very pale pink (the palest I can produce!), but in fact it is virtually colourless. The pale brown precipitate is oxidised to darker brown manganese(III) oxide in contact with oxygen from the air.

The reaction of hexaaquamanganese(II) ions with ammonia solution

Ammonia can act as both a base and a ligand. In this case, at usual lab concentrations, it simply acts as a base - removing hydrogen ions from the aqua complex.

Again, I have shown the original solution as the palest pink I can produce, but in fact it is virtually colourless. The pale brown precipitate is oxidised to darker brown manganese(III) oxide in contact with oxygen from the air.

There is no observable difference in appearance between this reaction and the last one.

Some potassium manganate(VII) chemistry

Potassium manganate(VII) (potassium permanganate) is a powerful oxidising agent.

Using potassium manganate(VII) as an oxidising agent in organic chemistry

Potassium manganate(VII) is usually used in neutral or alkaline solution in organic chemistry. Acidified potassium manganate(VII) tends to be a rather destructively strong oxidising agent, breaking carbon-carbon bonds.

The potassium manganate(VII) solution is usually made mildly alkaline with sodium carbonate solution, and the typical colour changes are:

In testing for a C=C double bond

Potassium manganate(VII) oxidises carbon-carbon double bonds, and so goes through the colour changes above.

Ethene, for example, is oxidised to ethane-1,2-diol.

The oxygen in square brackets is taken to mean "oxygen from an oxidising agent". This abbreviated form of the equation is most commonly used in organic chemistry. You are very unlikely to have to write the complete ionic equation for this reaction at this level.

To be honest, this isn't a good test for a carbon-carbon double bond, because anything which is even mildly reducing would have the same effect on the potassium manganate(VII) solution.

You could, however, use this reaction simply as a means of making the diol.

In the oxidation of aromatic side chains

Alkaline potassium manganate(VII) solution oxidises any hydrocarbon side chain attached to a benzene ring back to a single -COOH group. Prolonged heating is necessary.

For example:

In the case of the ethyl side chain, you will also get carbon dioxide. With longer side chains, you will get all sorts of mixtures of other products - but in each case, the main product will be benzoic acid.

Using potassium manganate(VII) as an oxidising agent in titrations

Background

Potassium manganate(VII) solution is used to find the concentration of all sorts of reducing agents. It is always used in acidic solution.

For example, it oxidises

• iron(II) ions to iron(III) ions

  

• hydrogen peroxide solution to oxygen

  

• ethanedioic acid to carbon dioxide (This reaction has to be done hot.)

  

• sulphite ions (sulphate(IV) ions) to sulphate ions (sulphate(VI) ions)

  

In each case, the half-equation for the manganate(VII) ions in acidic solution is:

These equations can be combined to give you an overall ionic equation for each possible reaction. That, of course, also gives you the reacting proportions.

For example, when the equations are combined, you find that 1 mole of MnO₄^- ions react with 5 moles of Fe²⁺ ions. Having got that information, the titration calculations are just like any other ones.

Doing the titration

The potassium manganate(VII) solution always goes into the burette, and the other solution in the flask is acidified with dilute sulphuric acid.

As the potassium manganate(VII) solution is run into the flask it becomes colourless. The end point is the first faint trace of permanent pink in the solution showing that there is a tiny excess of manganate(VII) ions present.

Problems with the use of potassium manganate(VII) solution

There are two things you need to be aware of:

• Potassium manganate(VII) can't be used in titrations in the presence of ions like chloride or bromide which it oxidises. An unknown amount of the potassium manganate(VII) would be used in side reactions, and so the titration result would be inaccurate.

  This is why you don't acidify the solution with hydrochloric acid.

• Potassium manganate(VII) isn't a primary standard. That means that it can't be made up to give a stable solution of accurately known concentration.

  It is so strongly coloured that it is impossible to see when all the crystals you have used have dissolved, and over a period of time it oxidises the water it is dissolved in to oxygen.

  Bottles of potassium manganate(VII) solution usually have a brown precipitate around the top. This is manganese(IV) oxide - and is produced when the manganate(VII) ions react with the water.

  You have to make up a solution which is approximately what you want, and then standardise it by doing a titration. This is often done with ethanedioic acid solution, because this is a primary standard.

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